So I am pretty excited. I had originally bought the book How to Prove It though Google online books. Unfortunately it was missing the intro chapter and there were a bunch other issues that made using it a pain (thought the fact that I have it on my iPad is cool since I pretty much have my iPad with me at all times).
Anyway I just finished reading the Intro chapter and have started working on some of the problems and I have to say, this book is so freaking cool. Just the exposure to some really cool math stuff that I have never seen before is totally worth the cover cost.
Couple highlights. So there are prime numbers of the form $$ 2^n-1 $$ where n is a prime. They are called Mersenne primes after a guy called, well of course by a monk (I think he was a monk now I am not so certain) named Mersenne (1588-1647). Mersenne primes are currently some of the largest prime number numbers in fact, the largest know prime is a Mersenne prime.
Anyway, that's kind of cool in a did you know this minutia kind of way. Here is the cool thing our buddy Euclid proved that if a prime number is of the form $$ 2^n-1 $$ then $$ 2^{n-1}(2^n-1) $$ is perfect. Meaning every Mersenne prime can be used to generate a perfect number.
Note a perfect number is a number n such that the sum of all its factors less than n = n. So for example 28 is a perfect number because its factors: 1,2,4,7,14 summed up equal 28.
What really got me though was later on Euler (1707-1783) proved that every perfect number is generated this way. So again using 28 as an example. $$28 = 2^2(2^3-1) $$.
So those were all pretty cool things. Here is something cool you can do with non prime numbers of the form $$ 2^n-1 $$ . If n is not prime then as a consequence $$ 2^n-1 $$ is also not prime. As a result we can take non Mersenne prime numbers of that form and factor them (if of course you know how to write them as $$ 2^n-1 $$ which I will agree is no mean feet and something I would really like to know how to do - maybe this would be a nice little programming project in the very near future.
Anyway, lets take a perfect number of this form, for example the one given in the book: 32,767 which equals $$ 2^{15}-1 $$, then we can two of its factors.
$$ 2^{15}-1 = 2^{3 \cdot 5}-1 $$
$$ = (2^3-1)(1+2^{3}+2^{3\cdot2}+...+2^{3\cdot4} $$
The general formula for this is: if $$n=a\cdot b $$ then $$2^n-1= 2^{a \cdot b}-1$$
$$ = (2^a-1)(1+2^a+2^{a \cdot 2}+...+2^{a \cdot (b-1)}) $$
Pretty cool right.
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